All Tasks - Asymptote

The figure shows : - part of a function $f$ - a line $r$ tangent to the graph of $f$ at the point with abscissa iqual to $2$ The value of $f'(2)$, derivative of the function $f$ at the point of abscissa $2$, can be equal to:

Consider $f(x)= 2 \arcsin\left(\dfrac{x}{3}\right)$ with domain $D_f=[-3, 3]$. Let $f'(x)$ be the first derivative of function $f(x)$, then $f'\left(1\right)$ is:

Let $f$ and $g$ be two differentiable functions in their domain, such that: $f(x)= \dfrac{\pi}{2} -2 \arcsin(1-2x)$ and $g(x)=x^2 f(x)$. Considering that $g'(x)$ is the first derivative of function $g(x)$, then $g'\left(\dfrac{1}{2}\right)$ is:

Consider $f(x)= 2 \arcsin\left(\dfrac{x}{3}\right)$ with domain $D_f=[-3, 3]$. The zeros of $f(x)$ are:

Consider $f(x)= \dfrac{\pi}{2} -2 \arcsin(1-2x)$ with domain $D_f=[0, 1]$. The solution of the equation $f(x)=f(0) + 2 \arcsin\left( \dfrac{\sqrt{3}}{2}\right)$ is:

Consider $f(x)= 2 \arcsin\left(\dfrac{x}{3}\right)$ with domain $D_f=[-3, 3]$ and range $D'_f = \left[ -\pi, \pi \right] $. The analytic expression of the inverse function of $f$, $f^{-1}(x)$, and $f^{-1}(\pi)$ are, respectively,