All Tasks - Asymptote

Solve the following trigonometric equation: $3arccot(x − \sqrt{3})− \pi=0$

Consider $a=tg(arccot(\sqrt(2))$. So the value of $a$ is:

Consider the function $f(x)=\dfrac{2\pi}{5}\text{arccot}\left(\ln(x+1)\right)$. The inverse functions of $f$, its domain ($D_{f^{-1}}$) and its range ($D'_{f^{-1}}$) are, respectively:

Let $f$ be the function defined by $f(x) =\pi-arccot(2x)$. So the inverse of $f$, $f^{-1}$, is the function defined by

The expression of the inverse function of $f(x)=2\text{arccot}(x+1)$ is:

The inverse function of the fucntion $f(x)=-\dfrac{3\pi}{2}\text{arccot}\left(\dfrac{2x+1}{3}\right)$ is: